itemDelimiter

[Mark Brownell]

On Thursday, February 12, 2004, at 03:14  PM, Thomas McGrath III wrote:

> Mark,
>
> Wow, this is more than I expected. Thank you.
>
> These functions seem to be the ticket for me. I will play with them 
> and try to understand them and report back.
>
> Thanks again,
>
> Tom

You're welcome.

If you have troubles determining how many paragraphs there are in a 
paragraph array then try this:
   -----------------------
   put 1 into countNum
   repeat
     put theParagraphArray[countNum] into zap
     if zap = empty then
       put (countNum - 1) into timesP
       exit repeat
     end if
     add 1 to countNum
   end repeat
   -- timesP now contains the number of <p>...</p> sets that where found.
   -----------------------

Mark